Question

A lorry moving at 60km h⁻¹ comes to rest in 30 minutes. Calculate its retardation, in km h⁻².

Answer 1

Answer:120 km/h^2

Step-by-step explanation:

Here u=60 kmph

v=0

t=30 min=1800 sec=0.5hr

Retardation(-a)=? in km/h^(2)

A=(v-u)/t=(0-60)/(0.5)

=(-60)×(2)=-120kmh^(-2)

Therefore (-a)=120km/h^2