Question

a lorry moving with uniform acceleration covers a distance of 180 m from point A to point B along a straight path in 15 s. its velocity, while passing through point B is 20 m per second. What is the velocity of the lorry at the time of passing through point A. What's the acceleration

Answer 1

Answer:

speed of lorry at A=4m/s

a=1.06m/s^2

Answer 2

Answer:

The velocity of the lorry at the time of passing through point A is 4 m/s and acceleration of the lorry is $1.06m/s^2$

Explanation:

Given the distance covered by the lorry, AB (d) = 180 m.

Time taken from point A to B, t = 15 s.

The initial velocty at A = u = ?

The final velocity  of lorry at point B, v = 20 m/s.

Formula for distance covered by a particle moving in a  straight line with uniform acceleration is given as,

$d=(\frac{v+u}{2})t$

substitute the given values, we get

$180m=\frac{u+20m/s}{2}\times15 s$

24m/s = u + 20 m/s

u = 4 m/s.

Now to calculate the acceleration of the lorry, use first equation of motion as,

v = u + at

20 m/s = 4 m/s + a x 15 s

$a=\frac{16m/s}{15 s} =1.06m/s^2$

Thus, the velocity of the lorry at the time of passing through point A is 4 m/s and acceleration of the lorry is $1.06m/s^2$.

#Learn More: equation of motion.

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