Math, asked by jasonjoshi5514, 1 year ago

A lot contains 12 items of which 4 are defective. three items are drawn at random from the lot one after the other. find the probability p that all three are non-defective.

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Answered by yashish11
0

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Answered by Agastya0606
1

The probability that all three are non-defective is 14/55.

Given,

A lot contains 12 items of which 4 are defective. three items are drawn at random from the lot one after the other.

To Find,

The probability that all three are non-defective.

Solution,

The total items in the lot are 12.

The number of defective items is 4.

So, the number of non-defective items will be 12-4 = 8.

Now, the probability that all three selected items are non-defective is

Probability = Favorable outcomes/Total number of outcomes

Favorable outcomes = 8C3 = 56

Total number of outcomes = 12C3 = 220

So,

Probability = 56/220 = 14/55

Hence, the probability that all three are non-defective is 14/55.

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