Question

A lot of 19 bulbs contains three defective forms one ball is drawn from the lord suppose the bulb drawn is not defective and is not replaced again a bulb is drawn from the rest find the probability that the sperm is not effective

Answer 1

Answer:

15/18

Step-by-step explanation:

There were 19 bulbs. One was taken away, which was not defective. So now, 18 bulbs exist with 3 defective bulbs in the lot.

To find probability

N(Event A) = 18- 3

N( total ) = 18

P( probability that the bulb is not defective) = 15/18

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Answer 2

Answer:

II)probability of this bulb being not defective =15/19