A lotus flower is blooming in a lake.The flower is 1/2metres above the surface of the lake.When the western wind blows,the flower droops at a distance of 2 metre from the base.Find the depth of the lake
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Assuming we are supposed to use trig on this problem, then we assume the lotus plant, at the end, was floating on the surface of the pond. So at the start, it was "hovering" 6 cm above the water. The wind blows it away, so now it's floating 10cm from where it was.
So now we have a triangle. (Sorry I can't do a picture.) The hypotenuse is the length of the lotus stem, call it h. The short leg along the top of the pond is 10 cm. The long leg is the depth of the pond, d. Pythagoras gives us d2+62=h2. But we know that h=d+6. So we have d2+102=(d+6)2, which gives d=163cm.
So now we have a triangle. (Sorry I can't do a picture.) The hypotenuse is the length of the lotus stem, call it h. The short leg along the top of the pond is 10 cm. The long leg is the depth of the pond, d. Pythagoras gives us d2+62=h2. But we know that h=d+6. So we have d2+102=(d+6)2, which gives d=163cm.
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