Question

(a^m/a^n)^m+n (a^n/a^l)^l+n (a^l/a^m)^m+l

Answer 1

Answer:

(a^m-n)^m+n×(a^n-l)^n+l×(a^l-m)^l+m

a^(m^2-n^2)×a^(n^2-l^2)×a^(l^2-m^2)

a^(m^2-n^2+n^2-l^2+l^2-m^2)

a^0=1