a^m^n=(a^m)^n explain m in the terms of n
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query:
(am)n=amn⇒amn=amnComparing exponents of both the sides,we getmn=mn⇒mnm=n⇒m(n−1)=n∴ m=n1(n−1)
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Answered by
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hope this helps you plz branlist
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