A machine gun fires 25g bullets at the rate of 600 bullets per minute with a speed of 200 m/s .Calculate the force required to keep the gun in a position?
Answers
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Answer:
The force that is required to keep the gun at its actual position is equal to 50N.
Step-by-step explanation:
We have given the mass of bullet = 25g = 25×10⁻³Kg
Gun fired 600 bullets in 1minute.
The time taken by one bullet = 60/600 = 1/10sec = 0.1sec
We can find the acceleration from the first equation of motion:
v = u - at ...............(1)
The bullet was at rest initially, u=0
The speed of bullet after being fired, v= 200m/s
Substitute the value of u, v and t in equation (1);
200 = 0 - (a)(0.1)
(0.1)a = 200
a = 2000m/s²
From the 2nd law of motion, force is given by,
F = ma
F = (25×10⁻³Kg)(2000m/s²)
F = 50N
Therefore, the force required to keep the gun in a position is equal to 50N.