Physics, asked by manishprik5326, 7 months ago

A machine gun fires 360 bullets per min and each bullet travels with a velocity of 60m/s of the mass of each bullet is 5gm find the power of the machine gun?

Answers

Answered by ashwinhacker5588
1

Answer: Given,

Number of bullets, n=360nos.

Mass of bullet, m

Power, =5400watt

Kinetic energy of 360 bullets, K.E=n×  

2

1

​  

mv  

2

=360×  

2

1

​  

×m×600  

2

=648×10  

5

mJ

Power=  

time

kineticenergy

​  

 

5400=  

60

648×10  

5

m

​  

 

m=5×10  

−3

kg=5gram

Hence, weight of each bullet is 5gram

Answered by shaharbanupp
0

Answer:

A machine gun fires 360 bullets per min and each bullet travels with a velocity of 60m/s of the mass of each bullet is 5gm. The power of the machine gun will be 54 \ Watt.

Explanation:

Power can be simply defined as the rate of work done or the amount of energy converted per unit time.

Power (P)  = \frac{Work\  done}{time} =\frac{W}{t}  ...(1)

Work done by the bullet will be equal to the change in kinetic energy which can be expressed as,

K.E = \frac{1}{2} m v^{2}  

where m -  mass of the bullet  

           v - velocity

Let n be the number of bullets,

then power becomes,

\text { Power }=n \times \frac{\frac{1}{2} m v^{2}}{t}

Or

P= \frac{n}{t} \times \frac{1}{2} m v^{2}    ...(2)

From the question,

m = 5 g = 5\times 10^{-3}  kg

v= 60\ m/s

\frac{n}{t}  = \frac{360\ bullets}{minute}

   =\frac{360}{ 60\ s}  =  6\ bullets\ per\ s

Substitute the above values into equation(2)

Equation (2) becomes,

P= 6 \times \frac{1}{2}\times 5\times10^{-3} \times 60^{2}

   = 54\ Watt

The power of the gun = 54\ Watt

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