Question

A machine gun fires a bullet of mass 40 g with a velocity 1200 ms^-1. The man holding it can exert a maximum force of 144 N on the gun. How many bullets can be fire per second at the most?

Answer 1

Answer:

3 bullets per second

Explanation:

The whole of the problem comes under one formula F = nmv

n is the number of bullets per second

m is the mass of each bullet

v is its velocity

144 = n×0.04×1200

You'd get n as 3.

Answer 2

$\Large{\underline{\bf{Given:}}}$

☞ Mass of bullet = 40g → 0.04kg

☞ Velocity 'v' = 1200m/s

☞ Maximum Force = 144N

$\Large{\underline{\bf{To\;Find:}}}$

☞ Number of bullets fired for a second.

$\huge{\underline{\underline{\sf{Solution:}}}}$

Let, Number of bullets per second be 'n'

✯ $\boxed{\sf{F × ∆t = ∆P}}$

✯ $\boxed{\sf{F = \frac{∆P}{∆t}}}$

As, P = mv

$→\;{\tt{F = \frac{n∆P}{∆t}}}$

$→\;{\tt{n = \frac{144}{0.04×1200}}}$

$→\;{\tt{n = \frac{144}{4×12}}}$

$➝\;{\bf{n = 3}}$

$\Large{\green{\underline{\underline{\mathfrak{AnSweR:}}}}}$

Number of bullets per second ◕➜ $\Large{\red{\mathfrak{3}}}$

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