Question

a machine gun fires a bullet of mass 40 g witha velocity 1200m/s. The man holding it can exert a maximum force of 144N on the gun. The number of bullets he can fire per second will be​

Answer 1

Answer:

3 bullets ps

Explanation:

Momentum p=mv. (m in kg)

p=0.04×1200

=>48 kg m/s

Number of bullets ps(per second) =144/48=3

Judging by the rate of fire, it's probably m4 carbine in burst mode.

Answer 2

Answer:answer is 3

Explanation: using the formula F = nmv/t

m=40g. t=1s

v=1200m/s

F =144N

Substitute in the formula :

F=nmv/t

=144=n×0.04×1200/1

=144=48n

=n=144/48

=3

Hope my answer is helpful