Question

Please solve this

${x}^{2} + 11x + 28$
​

Answer 1

$\boxed{\boxed{\huge{\green{\mathfrak{\underline{Answer}}}}}}$

${x}^{2} + 11x + 28 \\ x {}^{2} +4x + 7x + 28 \\ x( x+ 4) + 7(x + 4)$

$\boxed{\boxed{\huge{\green{\mathfrak{\underline{(x+7)(x+4)}}}}}}$

Answer 2

Answer:

x=-4 or x=-7

Step-by-step explanation:

let

${x}^{2} + 11x + 28 = 0$

then the roots of the equation are

by factorization

we get

${x}^{2} + 7x + 4x + 28 \\ \\ we \: do \: further \: simplification \: we \: \\ get \\ x(x + 7) + 4(x + 7) = 0 \\ \\ we \: can \: write \: as \: (x + 7)(x + 4) \\ roots \: or \: zeroes \: are \: x = - 7 \: or \: - 4$

so finally we get x=-4 or x=-7 as roots or zeroes

please mark this answer as brainliest answer