Question

A machine gun fires a bullet of mass 40g with a velocity 1200m/s. The mab holding it can exert a maximum force of 144N on the gun. How many bullets can he fire Per second at the most?

Answer 1

Given that m= 40*10^-3,f=144N v=1200m/s We know that force = dp/dt means that change in momentum is called force Then p=mv hence f= d(mv)/dt but find out n bullets per seconds Then f=mvn/t 144=n *40*10^-3*1200/1 hence n=3

Answer 2

Answer:

Explanation:

Given :   m=40 g =0.04 kg            v=1200  m/s            F=144 N

Let n be the number of bullets that can be fired per second.

The force exerted by man must balance the change in momentum of the bullets per second.

∴     F=mnv

OR    144=0.04×v×1200            ⟹n=3 bullets per second