A machine gun has a mass of 20kg. It fires 30g bullets at the rate of 400 bullets per second with a speed of 400 m/s. What force must be applied to the gun to keep it in position ?
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Answered by
6
Answer:
force =rate of change of linear momentum
no of bullets per sec=400bullets/sec
n(mv)=f
f=400×30×400/1000
=4800N
Answered by
6
Answer:
The formula to find the force in this question is :
F = nmv
n = no. of bullets per second
m = mass of bullet
v = velocity of bullet
F = nmv
= 400 × 0.03 × 400
= 4800 N
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