Physics, asked by wahib432, 1 year ago

A machine gun has a mass of 5kg.It fires 50 gram bullets at the rate of 30 bullets per minute at a speed of400m/s.What force is required to keep the gun in position.

Answers

Answered by udayjogi
121
application of Newton's second law
Attachments:
Answered by branta
84

Answer: The correct answer is 10 N.

Explanation:

Calculate the change in the momentum for the 30 bullets by converting the mass of the bullet into kilogram and multiply it with velocity of the bullet.

Change in momentum= 50\times 10^{-3}\times 30\times 400

The expression for the force in terms of the change in momentum is as follows by using Newton's second law;

F=\frac{Changeinmomentuminbullets}{Time\ taken}

It is given in the problem that A machine gun has a mass of 5 kg.It fires 50 gram bullets at the rate of 30 bullets per minute at a speed of 400 m/s.

Put t= 1 min= 60 s and Change in momentum= 50\times 10^{-3}\times 30\times 400.

F=\frac{50\times 10^{-3}\times 30\times400}{60}

F=10 N

Therefore, the force required to keep the gun in position is 10 N.

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