Question

A machine gun of mass 25 kg fires a bullet of mass 30 gram with a velocity of 250 m/s. Find the velocity With which the machine gun will recoil​

Answer 1

Answer:

v 190 \ 40

_ 25 is not genus

Answer 2

Answer:

Change in momentum of one bullet in one second   ΔP1=mbulletubullet−0

⟹ ΔP1=0.025×500=12.5 kg m/s

Number of bullets fired in one second  n=4

Thus total change in momentum in one second   ΔPtotal=nΔP1=4×12.5=50 kg m/s

Force applied to hold the gun is equal to the magnitude of change in momentum of the bullets in one second.

⟹ F=50 N