Question

A machine gun with a mass of 5kg fires a 50g bullet at a speed of 100m/s. The recoil speed of the machine gun is?

Answer 1

Answer:

1ms-1

Explanation:

Gun momentum = bullet momentum

5 x v = 0.05 x 100

v = 1 ms-1

Answer 2

$\large{\mathfrak{\underline{\underline{Answer:-}}}}$

${\mathfrak{\underline{\underline{Step-By-Step-Explanation}}}}$

Convert mass of bullet 50g in kg

✯ Divide 50 by 1000

⟹ 50/1000

∴ 0.05 kg

$\rule{200}{2}$

Initially:-

(Initially mass)

M1 = Mass of bullet + mass of Gun = 50 + 0.05

⟹ M1 = 50.05kg

v1(initial velocity) = 100 m/s

_______________________

Finally:-

(Mass)M2 = 50kg

v2 (final velocity) = ?

_________________________

Use law of Conservation of Momentum

$\huge{\sf{\boxed{\boxed{M_{1} {\times} V_{1} \: = \: M_{2}{\times}V_{2}}}}}$

____________________[Put Values]

50.05 * 100 = 50 * V2

⇒ V2 = 5050/ 50

⇒ V2 = 101

✯ V2 = 101 m/s

$\rule{200}{2}$

$\huge{\sf{\boxed{V_{2} \: = \: 101 m/s^{2}}}}$