Question

A machine is driven by a 100 kg mass that falls 8.0 m in 4.0 s. it lifts a load of mass 500 kg vertically upwards. Taking g = 10m/s2, the work done by the falling mass in its displacement by 8.0 m is​

Answer 1

Final speed of 100 kg stone when it is falling from 8 m height, v = begin mathsize 12px style square root of 2 cross times g cross times h end root space equals space square root of 2 cross times 9.8 cross times 8 end root space equals space 12.52 space m divided by s end style
(a) force = 100 × 9.8 = 980 N

(b) workdone? when an object falling in gravitational field, object does not do any work. Work is done on the object by gravitational field

(c) Input power = force × velocity = 100×9.8×12.52 = 12270 W

(d) power output = 0.75×12270 = 9202.5 W

(e) workdone by machine = 75% input power × time = .75×12270× 4 = 36810 J

Answer 2

Explanation:

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