a machine is purchased for rs625000.Its value depreciates at the rate of 8%p.a. what will be it's value after 2 years
.
.
with explanation.
no spam(~_~メ)
Answers
Answered by
1
Answer:
Value of the machine now: P = 625,000.
Rate of decrease in its value : 8% per annum. (depreciation)
Depreciation 1st year = P * 8/100 * 1 = 0.08 P
Value after 1 st year : P - P * 8/100 * 1
= 0.92 P
Value after 2nd year : 0.92 P - 0.92 P * 8/100
= 0.92 P (1 - 0.08)
= 0.92² P
= 0.92² * 625, 000 units
= 529, 000 units.
Answered by
1
Step-by-step explanation:
a machine is purchased for rs625000.Its value depreciates at the rate of 8%p.a. what will be it's value after 2 years
.
.
with explanation.
no spam(~_~メ)
i dont know
Similar questions