A machine overcomes a resistance of 1600 N through a distance of 0.12 m, when an effort of 400 N acts
through a distance of 0.96 m. Calculate (i) VR (ii) MA (iii) efficiency of the machine.
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Given info : A machine overcomes a resistance of 1600 N through a distance of 0.12 m, when an effort of 400 N acts through a distance of 0.96 m.
To find : (i) velocity ratio (ii) mechanical advantage (iii) efficiency of the machine
Solution : here load = 1600 N , effort = 400N , load arm = 0.12 m and effort arm = 0.96 m
(i) velocity ratio , VR = effort arm/load arm
= 0.96m/0.12m = 8
Therefore the Velocity ratio is 8.
(ii) mechanical advantage, MA = load/effort = 1600 N/400 N = 4
therefore value of MA is 4.
(iii) efficiency of the machine = MA/VR × 100
= 4/8 × 100 = 50 %
Therefore efficiency of the machine is 50%
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