a machine was purchased for rs 6000 if its cost depriciate to rs 5415 in 2 yrs find rate of its depreciation
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Answered by
4
6000-5415=585/2=292.50 is the depreciation per year
so 292.50*100=29250/6000=4.875 is the rate of depreciation
so 292.50*100=29250/6000=4.875 is the rate of depreciation
Answered by
5
previous price =6000
present price =5415
time=2yrs
let rate=x
present price =past price *(1-rate/100)²
6000=5415*(100-x/100)²
6000/5415=(100-x/100)²
400/361=(100-x/100)²
20/19=100-x/100
20*100/19=100-x
100-2000/19=x
x=-100/19
rate =100/19%
present price =5415
time=2yrs
let rate=x
present price =past price *(1-rate/100)²
6000=5415*(100-x/100)²
6000/5415=(100-x/100)²
400/361=(100-x/100)²
20/19=100-x/100
20*100/19=100-x
100-2000/19=x
x=-100/19
rate =100/19%
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