A magician has 12 coins in his pocket. Eight of these coins are normal fair coins (with one head and one tail) and four are defective coins with heads on both sides. The magician randomly draws a coin from his pocket and flips it. Given that the flipped coin shows a head, what is the probability that it is defective?
Answers
Answer:
probability that it is defective = 1/2
Step-by-step explanation:
A magician has 12 coins in his pocket. Eight of these coins are normal fair coins (with one head and one tail) and four are defective coins with heads on both sides. The magician randomly draws a coin from his pocket and flips it. Given that the flipped coin shows a head, what is the probability that it is defective?
There are 12 coins in pocket
8 are fair coins
4 are defective
probability of choosing Defective coin = 4/12 = 1/3
Probability of Flipping Head = 1/3
Probability of choosing Fair coin = 8/12 = 2/3
Probability of Flipping Head = (1/2)(2/3) = (1/3)
Probability of Flipping Head is equal from Defective & Fair Coins
=> probability that it is defective = 1/2
Answer:
A magician has 12 coins in his pocket. Eight of these coins are normal fair coins (with one head and one tail) and four are defective coins with heads on both sides. The magician randomly draws a coin from his pocket and flips it. Given that the flipped coin shows a head, what is the probability that it is defective?