Question

A magnetic dipole of magnetic moment 0.72 A m2 is placed horizontally with the north pole pointing towards south. Find the position of the neutral point if the horizontal component of the earth's magnetic field is 18 μT.

Answer 1

Explanation:

To Find the position of the neutral point if the horizontal component of the earth's magnetic field is 18 μT:

Step 1:

Given data in the question  :

The Magnetic Dipolar Moment,  $M=0.72 \mathrm{Am}^{2}$

Horizontal part of a magnetic field on Earth,$B_{H}=18 \mu T$

Let d be the distance from the dipole's South of the Neutral approach.

The neutral spot lies across the magnet's axial axis, if the magnet should be such that its north equator matches the regional south of the Earth

Step 2:

Consequently, the magnetic area at the dipole axial point (B) is given by

$B=\frac{\mu_{0} M}{4 \pi d^{3}}$

This force of the magnetic area should be equal to the horizontal part of the magnetic area on Earth.  

Accordingly,

$B=\frac{\mu_{0} M}{4 \pi d^{3}}$

On Substituting the values , we get

$\frac{10^{-7} \times 2 \times 0.72}{d^{3}}=18 \times 10^{-6}$

$d^{3}=\frac{10^{-7} \times 2 \times 0.72}{18 \times 10^{-6}}$

$d=\left(\frac{8 \times 10^{-9}}{10^{-6}}\right)^{\frac{1}{3}}$

$d=2 \times 10^{-1} \mathrm{m}=0.2, \mathrm{m}=20 \mathrm{cm}$

Answer 2

Answer:

Above answer is correct ......