A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip down at 60° with the horizontal. The horizontal components of the earth’s magnetic field at the place is known to be 0.4 G. Determine the magnitude of the earth’s magnetic field at the place.
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A magnetic needle free to rotate in a vertical plane parallel to the magnetic meridian has its north tip down at 60° with the horizontal. The horizontal components of the earth’s magnetic field at the place is known to be 0.4 G. Determine the magnitude of the earth’s
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एक चुंबकीय सुई चुंबकीय मध्याह्न करने के लिए एक ऊर्ध्वाधर विमान समानांतर में बारी बारी से करने के लिए स्वतंत्र 0.4 ग्राम पृथ्वी की की भयावहता का निर्धारण होने की जगह पर पृथ्वी के चुंबकीय क्षेत्र की क्षैतिज क्षैतिज घटकों के साथ 60 में जाना जाता है पर नीचे इसके उत्तर टिप है
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Angle of dip, θ = 60° H = 0.4G = 0.4 x 10–4T If Be is earth’s magnetic field, then H = Becosθ. More
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Answer: H=0.4G
Angle of dip=x=60 degree
V/H=tan60
V=H . tan60=0.4√3 G
B^2=H^2+V^2
=0.64
B=0.8G
Explanation:
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