In a first order reaction, the concentration of the reactant is reduced from 0.6 mol L⁻¹ to 0.2 mol L⁻¹ in 5 mins. Calculate the rate constant of the reaction.
Answers
The rate constant of the reaction is 0.08 mol/l-min.
Answer:
O.22/min is the rate constant for the given reaction.
Explanation:
The given reaction is first order reaction.
The concentration of reactant is reduced
Initial concentration = Ai = 0.6 mols/L
The concentration is recorded after five minutes.
Time = t = 5 mins
Final concentration = A = 0.2mols/L
Rate constant is given by the formula
k= 2.303/t * log (Ai/A)
=2.303/5 * log (0.6/0.2)
= 0.4606 * log 3
= 0.4606 * 0.4771
= 0.2197
=0.22/min
Hence, O.22/min is the rate constant for the given reaction.
Note:
Rate constant is basically proportionalaity constant.
It gives a relationship between rate of a reaction and the initial and final concentrations of the reactants. The specific rate constant is given by kk.
The value of rate constant depends upon the temperature.
In first order reaction, the rate is depending on only one reactant.