Question

A maharaj owned a mango tree that had very sweet, abundant fruit. People would come from miles to pick the fruit . So the maharaja decided to protect the tree by erecting a series of seven concentric fences around it. Each fence had a gate with a guard. To get to the tree , the person would have to pass through seven gates and pass seven guards. One day, a man approached the guard at the
first gate and said, "If you let me pass, when I come back I'll
bring you some mangoes. I will give you hall mangoes I have, but you must give me one back.
example, if he brings back 10 mangoes, he'll give five to the guard and the guard will give one back. The guard let the
man in the gate, and the man proceeded to make the same deal with the other six guards.
The question is: How many mangoes did the man have to get to pass back through the seven gates, giving half to each guard and the guard giving one back and still having 5 mangoes for him in the end.
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Answer 1

Answer:

386 Mangoes

Step-by-step explanation:

if Before Gate a man have x mangoes then after passing gate  man will have y

x - x/2  + 1 = y

=> x/2 + 1 = y

=> x = 2(y-1)

After passing 7th gate he had y(5) mangoes

=> x = 2(5-1)

=> x = 8

=> before 7th gate he had 8 mangoes  which is equal to after passing 6th gate

=> before 6th gate = 2(8-1) = 14

=> before 5th gate = 2(14-1) = 26

=> before 4th gate = 2(26-1) = 50

=> before 3rd gate = 2(50-1) = 98

=> before 2nd gate = 2(98-1)= 194

=> before 1st Gate = 2(194-1) = 386

So Man has to take 386 Mangoes to get finally 5 mangoes to get to pass back through seven gates.

Answer 2

Answer:

386 is answer dear friend