Math, asked by Anonymous, 1 year ago

A maharaj owned a mango tree that had very sweet, abundant fruit. People would come from miles to pick the fruit . So the maharaja decided to protect the tree by erecting a series of seven concentric fences around it. Each fence had a gate with a guard. To get to the tree , the person would have to pass through seven gates and pass seven guards. One day, a man approached the guard at the
first gate and said, "If you let me pass, when I come back I'll
bring you some mangoes. I will give you hall mangoes I have, but you must give me one back.
example, if he brings back 10 mangoes, he'll give five to the guard and the guard will give one back. The guard let the
man in the gate, and the man proceeded to make the same deal with the other six guards.
The question is: How many mangoes did the man have to get to pass back through the seven gates, giving half to each guard and the guard giving one back and still having 5 mangoes for him in the end.

Answers

Answered by antareepray2
56

As he has five mangoes at the last, so he should bring 8 mangoes to the last gate.

Similarly, he would have brought 14 to the fifth gate.

He would have brought 26 to the forth gate.

He would have brought 50 to the third gate.

He would have brought 98 to the second gate.

Hence, he plucked a total of 194 mangoes and he was left with five mangoes at last.

HOPE THIS COULD HELP!!!


Anonymous: plz give the solution
rajeshsharma061952: Can u plz give proper explanation what I mean is a calculation.... Plz.
shrishrigurudev: ya
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