Question

a mam is moving with the acceleration 1 m/sec from rest. Find the distance travelled by the man in 5th second

Answer 1

your ans

given:-

u=0 (man is moving from rest)

a=1

t=5

to find distance

applying:-

s=ut+1/2at^2

s=0×5+1/2×1×5×5

s=1/2×25

s==12.5m

Answer 2

$\textbf {ANSWER:}$

Given that:

u = 0 m/s ( as the car started from rest )

a = 1 m/s^2

t = 5 s

By applying the second equation of motion:

$s = ut + \frac{1}{2} a {t}^{2} \\ \\ = 0(5) + \frac{1}{2} (1) {(5)}^{2} \\ \\ = 0 + \frac{25}{2} \\ \\ = 12.5 \: m$