A man 1.5 m tall stands on top a light house 40 m high and sees a ship at a deppression of 35°.How far is it from the foot of the light house?
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Height of light house = 60 m
Angle of depression = 30 °
Let the distance of boat from the light house = s.
Then ,
angle of depression = angle of elevation height
tan ∆ of elevation = hieght by distance
tan 30 = 60/s
s = 60√3m
@loki
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