Math, asked by rish5856, 1 year ago

A man, a woman and a boy can complete a job in 3, 4 and 12 days respectively. How many boys must assist 1 man and 1 woman to complete the job in 1/4th of a day?; A man, a woman and a boy can complete a job in 3, 4 and 12 days respectively. How many boys must assist 1 man and 1 woman to complete the job in 1/4th of a day?

Answers

Answered by palak5354
8

If they have to complete the 12 units work in 14 of day .

So it means their combined efficiency should be 48 /day.

(1 man + 1 woman)'s efficiency

= 4+3 = 7 units

unit left = 48−7 = 41 units

Now No. of boys required

= T.Weff of a boy=411=41 boys

Answered by sharmilabegum1996
7

Answer:

Step-by-step explanation:

One man's one day work = 1/3

One women's one day work = 1/4

One boys one day work = 1/12

(1 man +1 woman) 1 days work

1/3+1/4=7/12

Remaining 1 days work 1-7/12= 5/12

Now, 1/12 work done by = 1 boy 51/2 work is done by

1*5/12

-------

1/12

12/1* 5/12=5

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