Question

A MAN Ś AGE IS SEVEN TIMES THAT OF HIS SON . IN 5 YEARS HE WILL BE FOUR TIMES AS OLD AS HIS SON . WHAT IS THE PRESENT AGE OF MAN AND HIS SON

Answer 1

HEY MATE YOUR ANSWER IS HERE!

Let the age of son be X years
Then, age of man is 7x years

After 5 years,
age of son = X + 5 years
age of man = 7x + 5 years
= 4 (X + 5) years
Therefore, the equation is:
7x + 5 = 4 (X + 5)
7x + 5 = 4x + 20
7x - 4x = 20 - 5
3x = 15
X = 5
So, their present ages are 5 yrs(son) and 35 yrs(man)

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