A man and a boy can do a piece of work in 24 days. If the man works alone for last 4 days, it is complete in 5 days. How long would the boy take to do it alone ?
Answers
Answered by
2
Step-by-step explanation:
(M+B)24 is Total Work.
=> (M+B)24 = (M+B)19+ (M)5
[Because now total work is completed in 25 days (Man alone does the work for last 5 days, therefore remaining work done by M+B for 20 days).]
By solving above equation:
=> M/B = 4/1 (Efficiency of M and B)
The boy will take to complete the work alone:
=> (M+B)24 = (B)D
=> (4+1)24 = (120)D
=> D = 120
Answered by
1
Answer:
(Man + boy)'s one days' work = 1/24
(Man + boy)'s 20 days' work = 20/24
= 5/6
Remaning 1/6 of the work is done by the man alone can do 1/30 of the work in 1 day.
Therefore Boy's one days' work
= 1/24 – 1/30
= 1/120
Therefore Boy would take 120 days to complete the work.
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