A man and a woman do a job independently in 24 days and 36 days respectively. They work together for 10 days and then a boy joins them. They finish the work in three additional days. How much time would the three of them have taken to do the job if all three started at the same time? A. 11 11/13days B. 99/4days C. 99/13days D. none of these
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Answer:
Let A work for x days before B joins him
So Total no of days A works = x+6 days
B works for 6 days
Total work done by both in 6 days = 6/24+ 6/36 = 1/4 +1/6= 5/12
Work remaining = 7/12
A will finish 7/12 of the work in 7/12 *24 = 14 days
Answer B joins after 14 days
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