A student multiplied a number by 5/11 instead of 11/5. what is the approximate percentage error in the calculation made?
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assume the value that are divide by both number
I assume x=15
First 3/5×15=9
Second (5/3)×15=25
Difference =25–9 = 16
Error %= difference ÷ error value × 100
= (16÷25)×100
= 64%
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