Question

a man approaches a plane mirror with a velocity v in a direction making an angle a with the normal to the mirror what will be the relative velocity of the image relative to the man.​

Answer 1

answer

The velocity of the man perpendicular to the mirror is given as Vcosθ

The image also approaches with the same velocity towards the man.

Thus the relative velocity is given as Vcosθ−(−Vcosθ)=2Vcosθ.

solution