Question

A man asked his neighbour et son
age. He replied in a mathematical
way. My son is five times as old
as
my daughter and my wife is
five times
as old as my son:
I am
am twice as old as my wife
Whereas
my grand mother, who is
(@te) Celebrating "hey eighty first
birthday is a old as all of us
put together
How old is the man's son?​

Answer 1

Answer:

he is 5 year old

Step-by-step explanation:

let the age of son = 5x

daughter = x

wife =25x

man = 50x

and all are equal to 81

and then solve it

it will give x=1

then put the value of x in the age of son

5x=5×1=5 years old

Answer 2

Step-by-step explanation:

let wife's age be x yrs.

Neighbors age=2x yrs.

let son's age be y yrs.

x=5y

y=x/5.

let daughter's age be z yrs.

x/5=5z

z=x/25 yrs.

sum of their all ages is 81 years.

=>x+2x+x/5+x/25=81

3x+6x/25=81

81x/25=81

x=25 years.

son's age=5 yrs.

fathers age =50 yrs.

his wife age =25 yrs.

daughter's age =1 yr.

please mark as BRAINLIEST.