Math, asked by yadavneelamny91409, 7 months ago

A man borrows * 10,000 at 5% per annum
compound interest. He repays 35% of the
sum borrowed at the end of the first year and
42% of the sum borrowed at the end of
the second year. How much must he pay at the
end of the third year in order to clear the debt?​

Answers

Answered by kevinskolkonto
1

Answer:

4156,425 on the third year

Step-by-step explanation:

10000×1,05 in one year debt, = 10500.

Repays 35%.

100-35=65% left.

0,65×10500= 6825.

Then in the second year there is once again an interest at 5%.

6825×1,05= 7166,25.

He then repays 42%.

100-42=58% left.

0,58×7166,25= 4156,425.

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