Question

a man borrows 10000 at 5% per annum compound interest is 35% of the sum borrowed at the end of first year and and 42% of sum borrowed at the end of second year how much much he paid at the end of third year in order to clear the debt​

Answer 1

Answer:

$\huge\tt\orange{Answer}$

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Step-by-step explanation:

Firstly,

For the first year,

P1 = 10000 , R = 5%

A1 = $= 10000 \times (1 + \frac{105}{100} )$

$= 10000 \times \frac{105}{1000} \\ = rs. \: 10500$

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At the end of the first year, he repays 35% of the sum borrowed so he repays the amount = 10500 in 35%

$= 10500 \times \frac{35}{100} \\ = rs. \: 3500$

Left amount = 10500 - 3500 = Rs. 7000

$\huge{Rs. 7000}$

For the second year,

P2 = Rs. 7000, R = 5%

A2 =

$= 7000(1 + \frac{5}{100} ) \\ = rs. \: 7350$

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At the end of the second year he repays 42% if the sum borrowed so he repays the amount =

$= 10000 \times \frac{42}{100} \\ = rs. \: 4200$

Left amount = 7350 - 4200 = Rs. 3150

$\huge{Rs. 3150}$

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For the

For the thrid year

P3 = Rs. 3150 , R = 5%A3 =

$3150(1 + \frac{5}{100} ) \\ = 3150 \times \frac{105}{100} \\ = rs. \: 3307.50$

Hence,he pays Rs. 3307.50 at the end of the third year in order to clear the debt.

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Answer 2

Answer:

3307.50

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