Math, asked by astudent72, 1 year ago

a man borrows rs 12000 at. 8% si for 2 years he repays rs 12000 at the end of 2 years and balance at the end of third year how mush dif he repay at the end of third year​

Answers

Answered by GulabLachman
1

Given:

(i) Principal value is Rs 12000, Rate is 8% and for 2 years.

(ii) He repays Rs 12000 and some additional money at the end of the 3rd year.

To find:

(i) The additional money paid at the end of third year.

Solution:

Given, Principal value (P) = Rs 12000

Rate (R) = 8% p.a.

Time (T) = 2 years.

We know,

Simple Interest (SI) = PRT/100

= (12000*8*2)/100

= Rs 1920.

So, total amount to be repayed = Rs (12000+1920)

= Rs 13920

He paid Rs 12000 at the end of 2nd year.

So, money repaid at the end of 3rd year

= Rs (13920-12000)

= Rs 1920.

So, the man needs to repay Rs 1920.

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