a man borrows rs 12000 at. 8% si for 2 years he repays rs 12000 at the end of 2 years and balance at the end of third year how mush dif he repay at the end of third year
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Given:
(i) Principal value is Rs 12000, Rate is 8% and for 2 years.
(ii) He repays Rs 12000 and some additional money at the end of the 3rd year.
To find:
(i) The additional money paid at the end of third year.
Solution:
Given, Principal value (P) = Rs 12000
Rate (R) = 8% p.a.
Time (T) = 2 years.
We know,
Simple Interest (SI) = PRT/100
= (12000*8*2)/100
= Rs 1920.
So, total amount to be repayed = Rs (12000+1920)
= Rs 13920
He paid Rs 12000 at the end of 2nd year.
So, money repaid at the end of 3rd year
= Rs (13920-12000)
= Rs 1920.
So, the man needs to repay Rs 1920.
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