Question

A man borrows Rs 6000 and repays with intrest of rs 240 in 30 installments if each installment is being more by rs 10 than previous installment ,find the first and last installment​

Answer 1

First installment was 63 Rs. and the last installment was 353 Rs.

Step-by-step explanation:

A man borrows the amount = Rs. 6,000

He repays the amount with interest = 6000 + 240 = ₹ 6,240

each installment is being more by Rs. 10 than previous installment.

Let the first installment be = x Rs.

Successive installments = x + 10, then x + 20, then x + 30 ...........

We will solve by using A.P. series formula :

$S=\frac{n}{2}[2a+(n-1)d]=6240$

Where A = first term = x

           n = total terms = 30

           d = difference = 10

Now put the values

$\frac{30}{2}[2x+(30-1)10]=6240$

30x + 4350 = 6240

30x = 1890

x = 63 Rs.  (first installment)

For last installment,

$T_{n} =a+(n-1)d$

$T_{30}=63+(30-1)10$

     = 63 + 290

     = 353 Rs.

Therefore, first installment was 63 Rs. and the last installment was 353 Rs.

Learn more about A.P. series : https://brainly.in/question/2525103

Answer 2

353

Step-by-step explanation:

first we have to use A. P series intis question