Question

A wave execute shm with maximum particle velocity vm. If displacement If 3/5 times of amplitude then particle velocity

Answer 1

Velocity of particle would be 4Vm/5

A wave executing simple harmonic motion with maximum velocity Vm.

we know, maximum velocity in shm, Vm = ωA .....(1)

where ω is angular frequency and A is amplitude.

given, displacement of particle, x = 3/5 A

so, v = ω√(A² - x²)

putting, x = 3/5 A

so, v = ω√(A² - 9/25 A²) = ω√(26/25 A²)

v = ω4A/5 = 4ωA/5

from equation (1) we get,

v = 4Vm/5

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Answer 2

$\huge\bold\purple{Answer:-}$

A wave executing simple harmonic motion with maximum velocity Vm.

we know, maximum velocity in shm, Vm = ωA .....(1)

where ω is angular frequency and A is amplitude.

given, displacement of particle, x = 3/5 A

so, v = ω√(A² - x²)

putting, x = 3/5 A

so, v = ω√(A² - 9/25 A²) = ω√(26/25 A²)

v = ω4A/5 = 4ωA/5

from equation (1) we get,

v = 4Vm/5