Math, asked by tanisha12356, 10 months ago

a man borrows rupees 6000 at 5% CI per annum if he pays rupees 1200 at the end of each year find the amount of the loan outstanding at the beginning of the third year​

Answers

Answered by amitnrw
8

Answer:

Rs 4155

Step-by-step explanation:

A man borrows rupees 6000 at 5% CI per annum if he pays rupees 1200 at the end of each year find the amount of the loan outstanding at the beginning of the third year​

Loan Amount = Rs 1200

Interest Rate = 5 % per annum

First Year interest = 6000 * 5 * 1 /100 = Rs 300

Paid after 1st year = 1200

So remaining Loan at beginning of 2nd Year = 6000 + 300 - 1200 = Rs 5100

2nd Year interest = 5100 * 5 * 1 /100 = Rs 255

Paid after 2nd year = 1200

So remaining Loan  at beginning of 3rd Year =  5100 + 255 - 1200 = Rs 4155

the amount of the loan outstanding at the beginning of the third year​ = Rs 4155

Answered by sneha413639
5

Answer:

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