a man borrows rupees 6000 at 5% CI per annum if he pays rupees 1200 at the end of each year find the amount of the loan outstanding at the beginning of the third year
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Rs 4155
Step-by-step explanation:
A man borrows rupees 6000 at 5% CI per annum if he pays rupees 1200 at the end of each year find the amount of the loan outstanding at the beginning of the third year
Loan Amount = Rs 1200
Interest Rate = 5 % per annum
First Year interest = 6000 * 5 * 1 /100 = Rs 300
Paid after 1st year = 1200
So remaining Loan at beginning of 2nd Year = 6000 + 300 - 1200 = Rs 5100
2nd Year interest = 5100 * 5 * 1 /100 = Rs 255
Paid after 2nd year = 1200
So remaining Loan at beginning of 3rd Year = 5100 + 255 - 1200 = Rs 4155
the amount of the loan outstanding at the beginning of the third year = Rs 4155
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