Question

a man bought 2 computers for ₹45000. He sold one at loss of 5% and other at gain of 5%. If the selling price of each set is same, find the cost price of each set.​

Answer 1

Answer:

Let one he bought at x ,

so, other = (45000-x)

A/q,

x*95/100 = (45000-x)*105/100

95x = 45000*105-105x

200x = 45000*105

x = 23625

so, other was bought at = 45000-23625 = 21375 (Ans)

Answer 2

The cost price of radio are Rs. 23048.77 and Rs. 21951.21.

Step-by-step explanation:

Given : A man bought two computers for rs 45000. he sold one at a loss of 5% and other at a profit of 5%. if the selling price of each set is same.

To find : The cost price of each set?

Solution :

Let the cost price of the radio be x and y.

So, .....(1)

We have given that,

Let x sold on 5% loss,

Selling price of x is

Let y sold on 5% profit

Selling price of y is

According to question,

Selling price of both radio is same.

So,

Substitute the value of x in (1),

Substitute in value of x

Therefore, The cost price of radio are Rs. 23048.77