Question

A MAN BOUGHT 2 TV SETS FOR RS42500 HE SOLD 1 AT A LOSS 10 PERCENT AND THE ANOTHER ONE AT THE GAIN OF 10 PERCENT .THEIR SELLING PRICE OF EACH SET IS THE SAME . DETERMINE THE CP of each set

Answer 1

Answer:

Let total cost of TV1 and TV2 be Rs 42,500

CP of TV1 = X

CP of TV2 – 42,500-X

SP of TV1 =  (CP –LOSS)

= X – 10 X/100  = 9X/10   ----  1

SP of TV2  = (CP + Gain)

= (42500 –X) + 10 (42500-X)/100

= 425000 – 10x +42500 – x      -----2

Equating 1 and 2 (since selling price of both tvs are same)

X = 835000/20   = 23375

X is cost price of TV1 = Rs 23375

Therefore, CP of TV2 = 42500-23375 = RS 19,125.

Ans:   CP of TV1 = 23,375 and CP of TV2 = 19,125

Step-by-step explanation: