A MAN BOUGHT 2 TV SETS FOR RS42500 HE SOLD 1 AT A LOSS 10 PERCENT AND THE ANOTHER ONE AT THE GAIN OF 10 PERCENT .THEIR SELLING PRICE OF EACH SET IS THE SAME . DETERMINE THE CP of each set
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Let total cost of TV1 and TV2 be Rs 42,500
CP of TV1 = X
CP of TV2 – 42,500-X
SP of TV1 = (CP –LOSS)
= X – 10 X/100 = 9X/10 ---- 1
SP of TV2 = (CP + Gain)
= (42500 –X) + 10 (42500-X)/100
= 425000 – 10x +42500 – x -----2
Equating 1 and 2 (since selling price of both tvs are same)
X = 835000/20 = 23375
X is cost price of TV1 = Rs 23375
Therefore, CP of TV2 = 42500-23375 = RS 19,125.
Ans: CP of TV1 = 23,375 and CP of TV2 = 19,125
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