Question

A man bought a certain number of oranges; out of which 13 percent were found rotten. He gave 75% of the remaining in charity and still has 522 oranges left. Find how many had he bought?

Answer 1

SOLUTION

let ,the number of oranges that he bought is X pcs......where X>0

• now 13%are rotten...

therefore the number of good oranges

$= x - x \times \frac{13}{100} \\ = \frac{(100 - 13)x}{100} \\ = \frac{87x}{100}$

• now 75% are donated to the charity.....

number of ORANGES left

$= \frac{87x}{100} (1 - \frac{75}{100} ) \\ = \frac{87 \times 25 \times x}{100 \times 100} \\ = \frac{87x}{400} \\ nowthe \: number \: of \: oranges \: lefted \: is \: 522 \\ therefore \\ \\ \frac{87x}{400} = 522 \\ x = \frac{522 \times 400}{87} \\ x = 2400$

ANSWER

SO HE HAS BOUGHT 2400 PCS OF ORANGES.......