Question

A man bought a horse and a carriage for Rs. 3000. He sold the horse at a gain of 20% and the carriage at a loss of 10% thereby gaining 2% on the whole. Find the cost of the horse

Answer 1

man bought a horse and a carriage = Rs. 3000
Let he bought a horse = Rs X
He bought a carriage = Rs (3000 - X)

DURING SOLD
He sold the horse at a gain of 20%
= X + (20X / 100)
= (6X / 5) ............... (1)
He sold the carriage at a loss of 10%
= (3000 - X) - [10(3000 - X) / 100]
= [(30000 - 10X) - (3000 - X) / 10]
= (27000 - 9X)..................... (2)

gaining 2% on the whole
3000 + [2(3000) / 100]
= 3060 ............. (3)

Therefore, by (1), (2) & (3)
(6X / 5) + [(27000 - 9 X) / 10)] = 3060
LCM is 10
[(12X + 27000 - 9X) / 10] = 3060
3X - 27000 = 30600
3X = 30600 - 27000
X = 3600 / 3
X = 1200
Cost of horse = Rs 1200

Therefore, the cost of the carriage = (3000-1200)
= 1800 Rs.

The cost of horse is Rs 1200 & cost of carriage is Rs 1800.

Answer 2

Answer:

Step-by-step explanation:

Let cp of the horse be rs. x ,then cp of the carriage =rs. (3000-x)

so, 20% of x-10% of (3000-x)=2% of.

3000

x/5-(3000-x)/10=60

2x-3000+x=600

3x=3600

x=1200

Hence the cp of the horse is=rs. 1200