A man bought some books for 1200rs. When the price of each rose by 30rs, he could buy 2 books less for 1200rs.
Find the original price of the book.
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Answer:
Step-by-step explanation:
no. of books = x
Total price = 1200rs.
cost of each book, original = 1200/x
new cost for each book = (1200/x)+30
no. of books he could buy now = x-2
therefore, (x-2){(1200/x)+30} = 1200
(x-2)[(1200+30x)/x] = 1200 = x[(1200-30x)/x] - 2[(1200-30x)/x]
(1200-30x)+(-2400+60x)/x = 1200 = [x(1200-30x)+(-2400+60x)]/x
(1200-30x)+(-2400+60x) = 1200*x/x= 1200
1200-30x-2400+60x = -1200+30x= 1200
30x = 2400
x = 2400/30 = 80
therefore, 1200/x = 1200/80 = 30
Thus, the original, price is 30rs.
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