A man bought two computers for ₹45000. he sold one at a loss of 5% and the other at a profit of 5% if the selling price of each set is same. find the cost price of each set
Answers
The cost price of first computer is Rs 23,625.
The cost price of second computer is Rs 21,375.
Given :
A man bought two computers for rs 45000. he sold one at a loss of 5% and other at a profit of 5%. The selling price of each set is the same.
To find :
find the cost price of each set.
Solution:
Let the cost price of one computer be x
The second computer be (45000-x)
Selling price:
he sold one at a loss of 5%:
100 - 5 = 95.
Loss on CP = 95x/100
He sold others at a profit of 5%:
100 + 5 = 105
Profit on CP = (45000-x)*105/100
Cost Price given : Selling price is same for each computer:
=> 95x/100= (45000-x)*105/100
=> 95x/100 = (45000 * 105)/100-105X/100
=> 95x/100 = 47250 - 105x/100
=> 95x/100 + 105x/100 = 47250
=> 200x/100 = 47250
=> 2x = 47250
=> x = 47250/2
=> x = 23625
So, the cost of first computer is Rs 23,625
The cost of second computer is 45000 - 23625 = Rs 21,375.
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