Question

a man buy a plot of agriculture land for rupees 3,60000 .he sells​

Answer 1

Step-by-step explanation:

A man buys a field of agricultural land for Rs. 3,60,000. He sells one-third at a loss of 20% and two-fifths at a gain of 25%. At what price must he sell the remaining field so as to make an overall profit of 10%?

First Method

CP = 3600000.

To gain 10% on whole land, SP = 360000 + 10% of 360000 = Rs. 396000.

1/3 of the land sold on 20% loss.

SP of 1/3 land = (360000/3) - 20% of (360000/3) = Rs. 96000.

SP of 2/5 of the land = (360000 * 2)/5 + 25% of (360000*2)/5 = Rs. 180000.

Thus, SP of the remaining land = 396000 - 96000 - 180000 = Rs. 120000.

Second Method

SP of total agricultural field at a profit of 10% = (360000*110)/100 = Rs. 396000.

So, SP of 1/3 of field = (360000/3)*(80/100) = Rs. 96000.

SP of 2/5th of the field =(2*360000*125)/(5*100) = Rs. 180000.

Hence,

SP of the remaining field = Rs. (396000-96000-180000).

= Rs. 120000.