a man buy some orange s at rupee 30 for 6 and an equal number of orange s at rupees 64for 8 he sells them at rupee 35 for 5 find his gain or loss percent
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Answer:
4
Step-by-step explanation:
He buys some oranges , say x oranges , at 20 for 60 Rs
20oranges=60Rs
1orange=60/20Rs=3Rs
xoranges=3xRs
Then he buys equal no. Of oranges = x , at 30 for 60 Rs
30oranges=60Rs
1orange=60/30Rs=2Rs
xoranges=2xRs
Total Cost Price = 3x + 2x = 5x Rs
He mixes two types of oranges and sells them at 25 for 60 Rs
25oranges=60Rs
1orange=(12/5)Rs
He had x+ x = 2x oranges to sell.
2xoranges=2x×(12/5)R=(24x/5)Ruppees
Selling price = ( 24x/5 ) Rs
C.P - S.P = 5x - (24x/5 )
Loss = x/5
Loss
=((x/5)÷5x)∗100
=(1/25)∗100=4
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